f(t) = F'(t) とすると、
∫[g(a)→g(b)] f (t) dt
= ∫[g(a)→g(b)] F'(t) dt
= F(g(b)) - F(g(a))
= ∫[a→b] (d/du F(g(u))) du
= ∫[a→b] F'(g(u)) g'(u) du
= ∫[a→b] f (g(u)) g'(u) du
最新の画像[もっと見る]
f(t) = F'(t) とすると、
∫[g(a)→g(b)] f (t) dt
= ∫[g(a)→g(b)] F'(t) dt
= F(g(b)) - F(g(a))
= ∫[a→b] (d/du F(g(u))) du
= ∫[a→b] F'(g(u)) g'(u) du
= ∫[a→b] f (g(u)) g'(u) du