①D(Cos√x)=Sin√x/2√x(ﾍﾞｯｾﾙ,三角関数合成関数)

①D(Cos√x)=Sin√x/2√x(ﾍﾞｯｾﾙ,三角関数合成関数)
②ﾚﾆﾑｽｹｰﾄ(r^2=a^2・Cos2θ)軌道
③d=∫1/(√x・Cos[√x])dx=
		～2Log[c+s/c-s]=		2Log[1+tanθ/1-tanθ]
ﾍﾞｰﾃの		⓪零点1/2±⒤		(複比)=d(光錐上距離p861)
γ(x)=1/(√x・Cos[√x]) -√(1 - x)
Solve[√x・Cos[√x]== 0, x]
∴x=0,π^2/4						≒2π
n	⋆	(π^2/4)・√n	⋆	文献値	⋆	文/()√n
1	⋆	2.467401095	⋆	14.13472	⋆	5.7286
2	⋆	3.489432092	⋆	21.02203	⋆	6.0245
3	⋆	4.273664059	⋆	25.01085	⋆	5.8523
4	⋆	4.934802189	⋆	30.42487	⋆	6.1654
5	⋆	5.517276575	⋆	32.93506	⋆	5.9694
6	⋆	6.043873673	⋆	37.58617	⋆	6.2189
7	⋆	6.528129681	⋆	40.91871	⋆	6.2681
8	⋆	6.978864184	⋆	43.32707	⋆	6.2083
9	⋆	7.402203284	⋆	48.00515	⋆	6.4853
10	⋆	7.80260736	⋆	49.77383	⋆	6.3791
11	⋆	8.183443638	⋆	52.97	⋆	6.4728
12	⋆	8.547328117	⋆	56.446	⋆	6.6039
13	⋆	8.896341164	⋆	59.347	⋆	6.6709
14	⋆	9.232169532	⋆	60.831	⋆	6.589
15	⋆	9.556203348	⋆	65.112	⋆	6.8136

仮定f(s)=f(1-s)ﾍﾞｰﾃ

仮定ξ(s)=ξ(1-s)ﾍﾞｰﾃ

∴d･λ(z)=(x+x^3/3+x^5/5+x^7/7+･･)(1-16q^2+128q^4ｰ704q^8+…）

ﾍﾞｰﾃγ(x)=1/(√x*Cos[√x]) -√(1 - x)