有識者会議

Keep your eye on the ball

コーヒーブレーク

2015-11-24 | 主題





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　　ランキング予測 次回投稿予定　:　2016 Brisbane International　　Brisbane, Australia　　ATP World Tour 250
　　　　　　　　　　　　　　　　　　Ferrer 準優勝以下 (Doha)　　　　7位
　　　　　　　　　　　　　　　　　　Ferrer 優勝、錦織 優勝　　　　　7位タイ
　　　　　　　　　　　　　　　　　　Ferrer 優勝、錦織 準優勝以下　　8位

錦織圭 2015 ATP World Tour Finals － Round-Robin 3rd SF進出条件

2015-11-19 | 錦織圭 ランキング
SF進出条件 : 錦織が Federer に勝ち、Djokovic が Berdych に負けた場合のみ。
　　Home | Barclays ATP World Tour Finals ＞ Score Centre ＞ Scenarios　　の条件を確認した。

Scenarios
Singles Group Stan Smith qualification scenarios after the completion of the second round of the event's group stage:
1) Regardless of score, if N. DJOKOVIC defeats T. BERDYCH and R. FEDERER defeats K. NISHIKORI, then R. FEDERER wins the group and N. DJOKOVIC qualifies 2nd.
2) Regardless of score, if N. DJOKOVIC defeats T. BERDYCH and K. NISHIKORI defeats R. FEDERER, then R. FEDERER wins the group and N. DJOKOVIC qualifies 2nd.
3) Regardless of score, if T. BERDYCH defeats N. DJOKOVIC and K. NISHIKORI defeats R. FEDERER, then K. NISHIKORI wins the group and R. FEDERER qualifies 2nd.
4) If T. BERDYCH defeats N. DJOKOVIC in 2 sets and R. FEDERER defeats K. NISHIKORI in 2 sets, then R. FEDERER wins the group and T. BERDYCH qualifies 2nd.
5) If T. BERDYCH defeats N. DJOKOVIC in 2 sets and R. FEDERER defeats K. NISHIKORI in 3 sets, then R. FEDERER wins the group and T. BERDYCH qualifies 2nd.
6) If T. BERDYCH defeats N. DJOKOVIC in 3 sets and R. FEDERER defeats K. NISHIKORI in 2 sets, then R. FEDERER wins the group and N. DJOKOVIC qualifies 2nd.
7) If T. BERDYCH defeats N. DJOKOVIC in 3 sets and R. FEDERER defeats K. NISHIKORI in 3 sets, then R. FEDERER wins the group and N. DJOKOVIC qualifies 2nd.

Semi-final Qualifying Procedure によると以下の手順で順位が決定されると思われる。
SF進出 : 勝利数 ＞ 試合数 ＞ ２選手タイは対戦勝者※ ＞ ３選手タイはセット率 ＞ ※ ＞ ゲーム率 ＞ ※ ＞ 直近月曜日ランキング順
　　※　セット率、ゲーム率で３選手のうち２選手が同じ場合、その２選手は対戦勝者が上位。


Home | Barclays ATP World Tour Finals ＞ Score Centre ＞ Format ＞Semi-final Qualifying Procedure

Semi-final Qualifying Procedure
The final standings of each group shall be determined by the first of the following methods that apply:
a) Greatest number of wins;
b) Greatest number of matches played;
Comment: 2-1 won-loss record beats a 2-0 won-loss record; a 1-2 record beats a 1-0 record.
c) Head-to-head results if only two (2) players are tied,
d) If three (3) players are tied, then:
If three (3) players each have one (1) win, a player having played less than all three (3) matches is automatically eliminated and the player advancing to the single elimination competition is the winner of the match-up of the two (2) players tied with 1-2 records; or
Highest percentage of sets won; or
Highest percentage of games won; or
The player positions on the Emirates ATP Rankings as of the Monday after the last ATP World Tour tournament of the calendar year.
If (i), (ii), (iii) or (iv) produce one (1) superior player (first place), or one (1) inferior player (third place), and the two (2) remaining players are tied, the tie between those two (2) players shall be broken by head-to-head record.

Comment 1: 1 player has 3 wins and the other 3 players have 1 win. Of the 3 players with 1 win, 1 player has only played in 2 matches while the other 2 players have played 3 matches. The player who has only played 2 matches is eliminated and then the 2 remaining players revert back to head-to-head results with the winner of their match advancing to the semi-finals.

Comment 2: 1 player has 3 wins and the other 3 players have 1 win and they all have played 3 matches.
The tie-break for % of sets won has 1 player with a better % than the other two. This player advances to the semi-final round.

Comment 3: 3 players have 2 wins and the other player has 0 wins. The player with 0 wins is eliminated. Of the 3 players with 2 wins, they are ordered by their % of sets won. This produces a 1, 2 & 3 order and the players finishing 1 and 2 move to the semi-final round and the player finishing 3 in % of sets won is eliminated. The player with the best % of sets won is the winner of the group.

Comment 4: 3 players have 2 wins and the other player has 0 wins. The player with 0 wins is eliminated. Of the 3 players with 2 wins, 1 player’s sets won-loss is 5-2 for 71.43%; the other 2 players both have a 4-3 record in sets for 57.14%. In this case there is 1 superior player (71.43%) and the remaining 2 players are tied; it now reverts to the head to head result of the 2 remaining players with the winning player advancing as group runner-up.

Comment 5: 3 players have 2 wins and the other player has 0 wins. The player with 0 wins is eliminated. Of the 3 players with 2 wins, 2 have set won-loss records of 5-3 (62.5%) while the other player is 4-3 (57.14%). In this case we have 1 inferior player (57.14%) and he is eliminated. The remaining two players both advance to the semi-finals with the winner of their head-to-head match advancing as the group winner.

Comment 6: 3 players have 2 wins and the other player has 0 wins. The player with 0 wins is eliminated. Of the 3 players with 2 wins, all have played 3 matches and all 3 have set won-loss records of 5-4 (55.56%). In this case we move to % of games won. The % of games won breaks down like this: 44-40 for 52.38%, 45-43 for 51.14% and 44-43 for 50.57%. This produces a 1, 2 and 3 order of the group and the number 1 player in % of games won is the group winner while the player finishing 2nd in % of games won advances to the semi-finals as the group runner-up. The player with the 3rd best % of games won is eliminated.