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white hole axiom ホワイトホール公理

2015-03-29 21:59:08 | 日記
THE AXIOM OBSERVATION DISTANCE=OBJEC^2
A------HUMAN-----B
A--HUMAN---------B <SPACE MOVEMENTSPACE MOVEMENT
is SAME ?
FAR BOX IS REAL HEAVY.
FAR BOX LOOK LIKE SMALL BY LIGHT DIFFUSION ?
=PRESENT PHYSICAL
SPACE is 3 DIMENSION TIME IS 1 DIMENSION
x-y-z-t space= xyz BOX where is time=1 DIMENSION?
FAR BOX REAL LIGHT
FAR BOX LOOK LIKE HEAVY BY PRINCIPLE OF LEVER.
FAR BOX IS REAL SMALL.
=MY AXIOM
SPACE IS 1 DDIMENSION TIME IS 2 DIMENSION
t-t-s time=DISK space=CIRCLE

EVERYTHING requested from OBSERVATION DISTANCE
Pi=3 Triangle
0-1-2-0 =1
0-1-2-0-3-4-0 =2
0-1-2-0-4-5-0-7-8-0 =3
0-1-2-0-4-5-0-7-8-0-10-11-0 =4
0-1-2-0-4-5-0-7-8-0-10-11-0-13-14-0 =5
0-1-2-0-4-5-0-7-8-0-10-11-0-13-14-0-16-17-0 =6

(P)=(C)108R=(D)54XR^2 (P)=(1/137X10^8)SEC=
[(54X10^5)/(137X10^8X108)]KM=60/360 ANGLE
(4X54X2X10^15KG)X(R/54X10^5KM)=(2X54^2X10^5SEC)X(R/54X10^5KM)
(54X10^5KM)=(1X10^15KELVIN)=(137X10^8KG/M)=(12X54X10^8X108RKM^3)

THE AXIOM OBSERVATION DISTANCE = OBJECT^2

Rate of reduction
P= OBSERVATION 1 L=27x2 minimum R=27
C= SPACE TEMPERATURE ROTATION ANGLE 1/27
D= WEIGHT SPEED TIME REVOLUTION ANGLE 1/86
G= DENSITY VOLUME 1/321

Q: From MR.A 10cm BOX Through (10M Distance) to Mr.B
PRESENT PHYSICS>>FROM Mr.A 10cm SEND (10M Distance) TO Mr.B 10cm box
OKA PHYSICS >> FROM MR.A LOOK 10KG BOX SEND (10M DISTANCE) TO MR.B 5cm
MR.B LOOK 5cm BOX RECEIVES(10M DISTANCE)FROM MR.A 10cm
SO 10cm GOLD HAND TO HAND TRADE RECEIVES > YOU LOOK 5cm I SEND 5cm GOLD NO DIRECT ACCESS
=5cm GOLD PROFIT :)
BIBLE IS NOT MISSTAKE.PRESENT PHYSICS MISSTAKE
Rate of reduction
P= OBSERVATION 1 L=27x2 minimum R=27
C= SPACE TEMPERATURE ROTATION ANGLE 1/27
D= WEIGHT SPEED TIME REVOLUTION ANGLE 1/86
G= DENSITY VOLUME 1/321



IT IS MODERN RELATIVITY GEOCERTRIC MODEL
SPECIAL THANKS CLAUDIUS PTOLEMAEUS ALBERT EINSTEIN PYTHAGORAS
YES CHRIST AND VATICAN IS TEACH PEOPLE TRUTH

WORLD FIRST ORIGINAL AXIOM BY YUUKI OKA NETURE

YES AXIOM CHRIST WORD MAKE TO NUMBER
DISTANCE=SPIN R X MASS
SPIN R=MASS
2 DIMENSION DISK IS TIME
1DIMENSION CIRCLE IS SPACE=G
DISTANCE SP-R-IN-G X MASS
I CALL THE ULTIMATE YES CHRIST AXION
IT IS UN-BELEV-ABLE NUTURE

OBSERVATION DISTANCE CONCERN AXIOM
(OBSERVATION DISTANC)=(SPIN R)X MASS(G) SPIN R=MASS
FOR EXAMPLE SOLO ROTATION SORO LEVOLITION
2 (LEVOLITION R)=T/S^2X3.14(RADIUSA A+RADIUSA B)^2=(OBSERVATION DISTANCE)
FOR EXAMPLE BINARY STAR CAR BLACK HOLE GALACTCY
DOUBLE PENDULUM TRIPLE PENDULUM

(CLASS CHANGE ENERGY THEORY)
1 GLOBE =216 R^3 P D=54R^2 P C=108/R P L=54P P=P
P>54>R/108>C>1/54R>D>1/216R>el

0-1-2-1-0 =3 0-1-2-3-2-1-0 =4 0-1-2-3-4-3-2-1-0 =5 0-1-2-3-4-5-4-3-2-1=6
0-1-2-3-4-5-1-5-4-3-2-1 =7 60/360
3X6/7/3=0.85(714285)^@ 3.14X6/7/3=0.89(714285)^@ 0.897597(714285)^@
3 IS LOST 1-2-0-4-5-0-7-8-0-10-11-0 SYSTEM 0-1>R
0-1 OBSERVER INPUT 1-0 OUTPUT 3=0 60/360 REPORT 3 IS LOST NUMBER O-1-2 OBJECT
R=1 ENVIR=6 (PYTHAGORAS) IS MISS R=1 ENVIR=18
Pi=18 R1=1X2X3^2 R2=2X2X3^2 R3=2X3X3^2 IS BINGO
2Pi=36R 2R=6 R=3 L DIMENSION IS 2X3^3 LIGHT P=1X2 (0.1)=OBSERVATION POINT=SOUL

(DOUBLE PENDULUM METHOD)
SIMPLE TALKING
A FIRST ROTATION = (1/4 ARM LENGTH =R)RING R'S CIRCLE
LEVOLITION OF R RING CORE SOLO FACTION
108R=T/(1/4X54XR^2)=S T=S/108XR >R=ROUTE 8
ROUTE 8=R RING CORE DISK VS AGAINST 90 ANGLE GRAVITY=ARM WEIGHT
A ARM WEIGHT+B ARM WEIGHT=MASS GRAVITY
MASS GRAVITY/2XROUTE 8X54=TIME DISK
IN SPACE OUT OF ERATH
ADD POWER SAME OF ARM WEIGHT(A+B)>[137X10^8X2ROUTE 8X54/ARM WEIGHT(A+B)]SPIN
IN ERATH DOUBLE PENDULUM IS 90 ANGLE AGAINST EARTH
EARTH MASS X (90 ANGLE X AXIS INCLINATION/60 ANGLE)=GRAVITY
[2X3.14XLENGTH FROM GVAVITY BAR/(2XROUTE 8X54)]=TIME DISK ANTI GRAVITY
GRAVITY/(2X54XR):ANTI GRAVITY=(3X10^5)/(137X10^8X6.28XR)KM=(ANSWER A)
100-ANSWE A % X 360 ANGLE/180 ANGLE AMPLITUDE ANGLE MOVEMENT AXION(MASS:R/2)

SUPER NOVA BECOME VISUALIZATION FUSION (TIME AND SPACE) WITH DIMEISION 90 ANGLE
SPIRAL VECTOR AGAINST GIRO ELECTRIC POWER CHANGED GRAVITY POWER
1/4 GLOBE>1/12 GLOBE=1/4 DISK>1/12 DISK=1/4 CIRCLE>1/12 CIRCLE=1/4 LINE>1/12 LINE=1/4POINT>1/12POINT
IT MEAN P>54>R/108>C>1/54R>D>1/216R>
[1/4 ANGLE>1/12 ANGLE FALL AND POWER WEAKEN AND =PHASE TRANSITION]
GRAVITY=SPACE AND ANTI GRAVITY=TIME PAIR STAND EVENT HORIZON WITH 90 DIMENSION ANGLE FLARE

COMPRESSION DIMENSION CHANGE THEORY
IN POINT C=54X10^5KM=1SEC
IN BAR=CIRCLE /2X54X R DIVISION
IN CIRCLE=DISK /54X RR DIVISION
BOTTOM IS CRRX54 CONE ANGLE IS TIME DISK
[(4)108R^3X54/H (5)243R^4X54/HH]IS NON SENSE

SPACE SIDE CALLED GIRO BLACK HOLE= 1 DIMENSION =TENSOR(1)
TIME SIDE CALLDE GIRO WHITE HOLE= 2 DIMENSION =TENSOR (1.-1) = (POSSIBLE TIME TRAVEL FREE)
SPACE AND TIME FUSION 90 DIMENSION ANGLE CALLED SUPER HOLE= 3 DIMENBSION =TENSOR (1.1.-1)

LHC ACCERATION SYSTEM ADD ENERGY = GRAVITY (LOW TENPERATURE VACCUM=LIKE SPACE MICROWAVE OVEN TIME MACHINE)
LOST ENERGY SYTEM CORE OF STAR = ANTI GVAVITY
IT CAN CONTROL 2 TIME DISK 1 SPACE CIRCLE
TIME GIRO=LOW TEMPERATURE VACCUM STOP (TIMETRON LASER) CAN MOVE ANTI GRAVITY MIRROR DISK
SPACE GIRO=HIGH TEMPERATURE DENSITY SPEED (GRAVITON LASER) CAN MOVE GRAVITY CIRCLE WORLD LINE
LOW ANGLE=TIME ADVANCES, HIGH ANGLE=TIME BACK,ZERO ANGLE=COSMOS CREATE, MAX ANGLE=THE END
CORE OF DIMENSION=ANTI GRAVITY , FACE OF DIMENSION=GRAVITY
TIMETRON LASER = OVER LIGHT SPEED DRIVE , GRAVITON LASER = GO TO PASS TIME
IF GO TO PASS TIME B3 = LOST B2 = ARRIVE B2-A3
TIME IS PLUS =POINT POWER , SPACE IS MINUS = FIELD POWER
1X1X1 1X1X6 9X9X9 9X9X6

TIME AND SPACE > INFORMATIONIZATION POINT THEORY
3X10^5KM X 86400 SEC/(6000KMX54)=137X10^8 SPIN
VIRTUAL ERATH FIELD SPIN 137X10^8 /SEC
FIELD IS NOT HAVE GRAVITY ,(SHADOW)
108X10^24 X 15X10^7 X 2 X [54/(86400X365)]^2KG=100% SPIN
MINIMUM SIZE =LIGHT SPIN R= 1 OKA
360 ANGLE =6 WORLD LINE ,2X54=60 ANGLE
54XR^2 DISK AND C HIGH 216 X C^3 VOLUME COSMOS R= 1C SEC
THINK OF SPIN 3X10^15 X 137X10^8 X 54
TIME IS (TOP KOMA) LOOK UP AND SIDE = GRAVITY FORCE
MASS 4X54X9X10^15 LIGHT KG lONGEVITY 180X10^4 LIGHT SEC

(P)=(C)108R=(D)54XR^2 (P)LIGHT=(1/137X10^8)SEC=[(54X10^5)/(137X10^8X108)]KM=50/360 ANGLE=1 OKA
(4X54X2X10^15KG)X(R/54X10^5KM)=(2X54^2X10^5SEC)X(R/54X10^5KM)=1 OKA^2
(54X10^5KM)=(1X10^15KELVIN)=(137X10^8KG/M)=(12X54X10^8X108RKM^3)


2X3.14XH=I (C)H=I
M1V1+M2V2=M1V1+M2V2 E=MST V=ST
E=[(4X54^2X10^15)X(R/54X10^5)]^3KM=[(2X54^2X10^5)X(R/54X10^5)]^3SEC=
{[(54X10^5/(137X10^8X108R)]/[(1/137X10^8)/(137X10^8X108R)]}^3MASS
PLUS-MINUS=54^3X4XR^2 PLUS-PLUS AND MINUS-MINUS = 108R
SPIN 1-137X10^8>>>54^3X4XR2/108R
MF=(D)+(C) DIMENSION EF=(C)(C) DIMENSION EMF=(D)(C)(C)(C)(C)=(5#) DIMENSION
EP=[(137X10^8SPIN)=(1X10^15 KELVIN)=(4X54^2X10^15KG)X(R/54X10^5KM)=(2X54^2X10^5SEC)X(R/54X10^5KM)=INSULATOR=MAX
EP=(1SPIN=0#KELVIN=0#KG=0#SEC)=SUPERCONDUCTVITY=MINIMUM SPIN GAP = VOLT
(1SPIN)VOLT EPMAX=0 AMPERE
EPMINIMUM=(137X10^8SPIN)=(1X10^15KELVIN)=(4X54^2X10^15KGX(R/54X10^15KM)=(2X54^2X10^5SEC)X(R/54X10^5KM)AMPERE
DU=?Q-?W>>>1 GT(1.-1)=1 TT(-1.1) CONSIST [(54X10^5)/(137X10^8X108R)]=(1/137X10^8) CHANGE

[CATERPILLAR SCHEDULE THEORY] GO TO PASS TIME = B3 TIME-JUMP 1 CHANCE
B2 LOST MASS ,B2-A3 CREATE LINE ,SAME TIME LINE IS LOST ENERGY 108^2X(P)LIGHT


a1a2()a4
()b1a3b3
c1c2b3c4

------a3----
--a1a2b3a4--
b1b2c3b4b5()
--c1c2d3c4--
------()----

Q.LENGTH 1/6C A-B A IS BAR STOP ANGULAR VELOCITY 2X3[RAD/YEAR] SPIN B SPEED IS ?

BAD ANSWER= 1250X10^8X3^2 KM

GOOD ANSWER=MASS 12X3X10^15X99.999999%KG SPACE LENGTH 5X10^4KM
1250X10^8X3^2KM/YEAR LEVOLITON 10^5KM/YEAR ROTATION
CORE TEMPERATURE 167X10^12KELVIN FACE TEMPERATURE 80KELVIN
CORE 240X10^7KG/M FACE 0.0001KG/M 1X10^4M^3
LEVOLITION ANGLE 89^90 ROTATION ANGLE 89^90
LIFE TIME 179X10^4SEC
=IT SCORE IS IF YOU LIVE CORE POINT OBSERVATION


if(Pi=3)? if(Pi=3.14)?

OBSERVATION POINT ?????????? OBSERVATION CIRCLE (SPACE TEMPERATURE WEIGHT ROTATION ANGLE)
OBSERVATION DISK (TIME SPEED LEVOLITION ANGLE) OBSERVATION GLOBE (MASS DENSITY)

TOMMOROW APPLE RATHER THAN TODAY APPLE.
4M DISTANCE APPLE IS 100KG BUT 16m DISTANCE APPLE IS 10KG
WE LIVE IN 2 TIME DISK AND 1 SPACE CIRCLE WORLD
YES CHRIST WORD MAKE TO NUMBER

I NAMED THIS THOERY = THE GREAT YES CHRIST AXIOM

1 GLOBE =216 R^3 P D=54R^2 P C=108/R P L=54P P=P
P>54>R/108>C>1/54R>D>1/216R> = CLASS CHANGE ENERGY THEORY

0-1-2-1-0 =3 0-1-2-3-2-1-0 =4 0-1-2-3-4-3-2-1-0 =5 0-1-2-3-4-5-4-3-2-1=6
0-1-2-3-4-5-1-5-4-3-2-1 =7 60/360
3X6/7/3=0.85(714285)^@ 3.14X6/7/3=0.89(714285)^@ 0.897597(714285)^@
3 IS LOST 1-2-0-4-5-0-7-8-0-10-11-0 SYSTEM 0-1>R
0-1 OBSERVER INPUT 1-0 OUTPUT 3=0 60/360 REPORT 3 IS LOST NUMBER O-1-2 OBJECT
R=3 ENVIR=6 (PYTHAGORAS) IS MISS Pi=18 R1=1X2X3^2 R2=2X2X3^2 R3=2X3X3^2 IS BINGO
2Pi=36R 2R=6 R=3 L DIMENSION IS 2X3^3 LIGHT P=1X2 (0.1)

P=1 C=54 D=3/108 G=1/54x3 el=1/216x3 is MINIMUM BIT
P=1 P-C-P=27 P-C-D-C-P=1/54 P-C-D-G-D-C-P=1/172 P-C-D-G-el-G-D-C-P=1/642
Pi=54 REAL 54 =LOOK Pi=3 PYTHAGORAS

ALBERT EINSTEIN THINK E>C>D P>C 2x3.14R P>D 3.14xR^2 Pi=3.14 E=?
P>C 2x3.14R is NO R line>C line 2x3.14R is yes HOW TO OBSERVATION ?

I THINK P>C>D>G>E P>C=54 3x7/6(714285)-(12045078) LOST 3 60/360 E=0-1.1-0 0=OBSERVATION POINT=SOUL
P=1 C=54 D=3/108 G=1/54x3 el=1/216x3 is MINIMUM BIT
P=1 P-C-P=27 P-C-D-C-P=1/27 P-C-D-G-D-C-P=1/86 P-C-D-G-el-G-D-C-P=1/321
Pi=54 REAL 54 LOOK 27 OKA / LOOK Pi=3 REAL 6 PYTHAGORAS

DISTANCE=SPIN R X MASS 1>27>1/27>1/86>1/321 class change energy (0-1-0) REAL energy is x2 (0-1)

the world consist of 2 time line and 1 space line xt yt zs

Observation distance Axiom
(Observation distance)=(Spin's Radius)xmass(Inverse proportion)^2
For Example : solo Rotation , solo Levolution
2s=t:1/s^2x3.14r^2=(Observation distance) r=Radiusa+Radiusb
 For Example : Binary star , Car Blackhole , Galactcy
This level is like a Pythagoras Axiom Discovery
star spin radius and everything spin radius circle(2)dimension
> no concern with mass gravity.
only spin speed concern with mass gravity Line(1)dimension

supernova became Visualization fusioned (black hole and white hole) with Dimension 90 angle.
spiral Vector against giro electric power changed gvavity power.
gravity and anti gravity pair stand Spinning Event Horizon with Dimension 90 angle Flare.
point dimension, C=1sec=300000km energy.
bar dimension 2rx3.14
square dimension rrx3.14
must division.
Bottom is Crrx3.14 cone angle = time bar
(4) dimension 12rrr3.14/h
(5) dimension 36rrrr3.14/hh is non sense
space side called giro black hole
time side called giro white hole
space and time fusion 90 dimension angle called super hole
acceraion system like LHC add energy = gravity
lost energy like core of star system = anti gvavity
it can control 2 time spin circle dimension and 1 space bar dimension
time giro ( Low temperature vacuum stop) timetron Laser can move time dimension and
space giro(High temperature Density speed) graviton Laser can move space dimension
low angle = time advances
high angle = time back
zero angle = cosmos create
max angle = cosmos end
core of dimension = anti gravity
face of dimension = gravity
gravity mirror change it easy
timetron Laser = Over light speed drive
graviton Laser = travel to pass time
if go to b-3 = lost b-2 = arrive b2-a3
time is plus on point space is minus on field
1x1x1 x1x1x6 9x9x9 x9x9x6
300000km x86400sec/(6000kmx3.14)=137x10^8 spin
earth in field spin 137x10^8 par sec
field is not have gravity cone have Weight.
6x10^24x15x10^7x2x(3.14/(86400x365))^2kg = 137x10^8x365 light spin
it score call 1 SUN
137x10^8 light electron spin = 1sec =30x10^5km
Gravitational filed = 1sun/(137x10^8x365)kg =100% spin
go to pass time 1>36 light lost in 1 chance
go to future 1>36 light create in 1 chance
minimum size = light spin r = called (1 oka)
360 angle = 6 world Interpretation = 2x3.14 = 60 angle
3.14rr field and C high 12.56ccc Volume
cosmos r =1Csec or 3Csec
think of spin 30x10^15x137x10^8x(9x3.14 or 3.14)
time is (top) look up and side = gravity force
mass 4x3.14x9x10^15 light kg Longevity 180x10^4 light sec
30x10^4km/oka=10x10^9/oka K = 1oka-137x10^8oka Density
30x10^5km=1sec=60 angle=137x10^8 light spin
1 time 1 space can go to pass time easy
you must look LHC shadow

(P)=(L)6r=(C)3r^2 (P)light=(1/137x10^8)sec=((3x10^5)/(137x10^8x6r))km=60/360 angle=1okaa
(4x9x10^15kg)x(r/3x10^5km)=(18x10^5sec)x(r/3x10^5km)=1okab
(3x10^5)km=(1x10^15)℃=(137x10^8)(kg/m)=volume(12x3x10^15)km=1okac

2x3.14xrxH=I (L)H=I
m1v1+m2v2=m2v1+m2v E=mst v=st
E=((4x9x10^15)x(r/3x10^5))^3km=((18x10^5)x(r/3x10^5))^3sec
=(((3x10^5/(137x10^8x6r))/((1/137x10^8)/(137x10^8x6r)))^3 mass
dU=δQ-δW>>> 1 GT(1,-1)=1 TT(-1,1) consist ((3x10^5)/(137x10^8x6r))=(1/137x10^8)changed。
(Caterpillar-schedule-theory)go to pass time = b3  time-jump 1 chance 
b2-lost-mass b2-a3 create-line same time line is = ,same space line is =
,but same (1time & -1space)tensor circle is lost energy 6^2x(P)light

New Ohm's law

plus-minus=27x4xr^2 plus-plus and minus-minus=6r
spin 1 - 137x10^8 >>> 108xr^2 : 6r
MF= (C)+(L)Dimension EF=(L)+(L)Dimension EMF=(C)(L)(L)(L)=(5#)Dimension
EP=((137x10^8spin)=1x10^15K=(4x9x10^15kg)x(r/3x10^5km)=(18x10^5sec)x(r/3x10^5km))
=insulator=MAX EP=(1spin=0#K=0#kg=0#sec)=Superconductivity=Minimum
Spin Gap= V (1-137x10^8)V EPMAX=0 ampere
EPMINIMUM=(137x10^8spin)=1x10^15K=(4x9x10^15kg)x(r/3x10^5km)=(18x10^5sec)x(r/3x10^5km)ampere


Caterpillar schedule thoery must go to pass time and teturen


a1a2()a4
()b1a3b3
c1c2b3c4

------a3----
--a1a2b3a4--
b1b2c3b4b5()
--c1c2d3c4--
------()----

to be continues

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